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RE: Dropping the Local Overbooking Multiplier (LOM) method from DS-TE specs?
- To: <te-wg@ops.ietf.org>
- Subject: RE: Dropping the Local Overbooking Multiplier (LOM) method from DS-TE specs?
- From: "Ash, Gerald R (Jerry), ALABS" <gash@att.com>
- Date: Sun, 1 Jun 2003 18:58:42 -0500
- Cc: "Ash, Gerald R (Jerry), ALABS" <gash@att.com>, "Lai, Wai S (Waisum), ALABS" <wlai@att.com>
All,
I'm not sure where we stand on keeping LOM or dropping LOM.
If we keep LOM, it is possible to re-define LOM so as to simplify the rather complicated 3-way approach to overbooking that now exists:
LSPOMc = LSP overbooking multiplier for CTc
LSOM = link size overbooking multiplier
LOMc = local overbooking multiplier for CTc
If LOM is retained, Wai Sum and I propose to redefine LOM (calling it LOM') to provide an overall simplification of this 3-way overbooking complexity, as follows.
Define:
LSPOMc = LSP overbooking multiplier for CTc
LSOM = link size overbooking multiplier
LSOM = maximum reservable bandwidth/maximum link bandwidth
LOMc = local overbooking multiplier for CTc (original definition of LOMc)
LOM'c = redefined local overbooking multiplier LOMc for CTc
LOM'c = LSOM * LSPOMc * LOMc
Given:
requested LSP CTc = RSVP-TE Tspec LSP bandwidth specified in TLV
Then the following general equation applies:
reserved CTc = requested LSP CTc/LOM'c (1)
wherein there are several cases of equation (1) for reserved CTc:
1. Link Size Overbooking only:
LSPOMc = 1, LOMc = 1, for all c
LOM'c = LSOM, or equivalently
reserved CTc = requested LSP CTc/LSOM = requested LSP CTc/LOM'c
2. LSP Size Overbooking only:
LSOM = 1, LOMc = 1, for all c
LOM'c = LSPOMc for all c, or equivalently
reserved CTc = requested LSP CTc/LSPOMc = requested LSP CTc/LOM'c
3. Both Link Size Overbooking and LSP Size Overbooking:
LOMc = 1, for all c
LOM'c = LSOM * LSPOMc, or equivalently
reserved CTc = requested LSP CTc/(LSOM * LSPOMc) = requested LSP CTc/LOM'c
4. LOM in conjunction with the above cases 1, 2, or 3
reserved CTc = requested LSP CTc/LOM'c
In this model, the aggregate constraint becomes:
o SUM (Reserved(CTc)) <= MLBW (2)
for all "c" in the range 0 <= c <= (MaxCT-1)
We believe that this simplification, as summarized in equations (1) and (2) above, is worthwhile if LOM is retained.
Comments welcome.
Thanks,
Jerry & Wai Sum