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RE: draft-ietf-rap-auth-policy-data-00.txt
Thanks for your feedback, Tom.
Yes, the intent is to have a reordered windowing algorithm as you describe
below. It would appear that the document's wording does not convey this
effectively enough. I can certainly pull in what you have written below
and tighten up the other references in the next draft.
Rodney
-----Original Message-----
From: Hall, Tom G. [mailto:Tom.G.Hall@wcom.com]
Sent: Monday, July 02, 2001 3:02 PM
To: 'rap@ops.ietf.org'
Subject: Re: draft-ietf-rap-auth-policy-data-00.txt
Good Day All,
Seems like a good idea; overall, a very well written draft.
I had a few problems understanding the wording in places,
but that will change as the draft heads toward RFC status.
- - -
I encourage anyone and everyone to pursue the key
management issue. (pg.11) "It is likely that the IETF
will define a standard key management protocol." We
really need this.
- - -
I got a bit confused about the validation of sequence
numbers. In one place it talked about storing the last
N sequence numbers, then in another it said that a
receiver only needs to save the highest sequence number
seen, then later on I see a 'reordering window' that
will allow for limited ... well, reordering of sequence
numbers. But then it says something about both storing
a number and therefore removing a number from the lower
end of the list (reorder window).
I shouldn't complain unless I'm ready to offer an
alternative, so I propose the following text to describe
the use of reordering windows for sequence numbers:
- - -
(all sequence numbers computed modulo 2^64)
An authenticating receiver maintains a 'reorder window'.
The window consists of a list of N consecutive sequence
numbers. (N >= 1) The list shall begin with an initial
sequence number generated as described in Section 3.
Each number in the list shall have an associated 'flag'
which indicates whether or not the receiver has received
that sequence number in a request message.
The authenticating receiver shall:
(1) Reject any sequence number less than the smallest number
in the list.
(2) Reject any sequence number in the list that has been
seen before.
(3) Accept any sequence number in the list that has never
been seen before, and then flag that number as having been
seen.
(4) Accept any sequence number (S) greater than the largest
number in the list, and then create a new list containing
the numbers S-N+1 through S, inclusive, along with the flags
any numbers that also appeared in the old list.
Example: (reorder window of size 10, Initial Sequence
Number =35,'+' means seen, and '-' means unseen)
Event List
----- ----
Start 35-, 36-, 37-, 38-, 39-, 40-, 41-, 42-, 43-, 44-
Get 37 35-, 36-, 37+, 38-, 39-, 40-, 41-, 42-, 43-, 44-
Get 36 35-, 36+, 37+, 38-, 39-, 40-, 41-, 42-, 43-, 44-
Get 35 35+, 36+, 37+, 38-, 39-, 40-, 41-, 42-, 43-, 44-
Get 32 (reject as too small)
Get 41 35+, 36+, 37+, 38-, 39-, 40-, 41+, 42-, 43-, 44-
Get 36 (reject as duplicate)
Get 42 35+, 36+, 37+, 38-, 39-, 40-, 41+, 42+, 43-, 44-
Get 48 39-, 40-, 41+, 42-, 43-, 44-, 45-, 46-, 47-, 48+
Note that this algorithm also works for the strict case
where N = 1.
- - -
Regards,
-- Tom